Risolvi le seguenti espressioni:

Esercizio 1 \[ \frac{4}{3}\div\frac{2}{3}+3\times\frac{5}{6}+\left(\frac{4}{5}+2\times5\right)= \] \[ \frac{4}{3}\div\frac{2}{3}+3\times\frac{5}{6}+\left(\frac{4}{5}+10\right)= \] \[ \frac{4}{3}\div\frac{2}{3}+3\times\frac{5}{6}+\frac{54}{5}= \] \[ \frac{4}{3}\times\frac{3}{2}+3\times\frac{5}{6}+\frac{54}{5}= \] \[ 2+\frac{5}{2}+\frac{54}{5}=\frac{20+25+108}{10}=\frac{153}{10}=15,3 \]

Esercizio 2 \[ \frac{4}{3}+\frac{2}{9}-\left[3\times\frac{1}{9}+\left(\frac{4}{3}+2-\frac{5}{3}\right)\times\frac{1}{2}\right]+3\times\frac{5}{3}+\left(\frac{4}{5}+2\times2\right)= \] \[ \frac{4}{3}+\frac{2}{9}-\left[3\times\frac{1}{9}+\left(\frac{4+8-5}{3}\right)\times\frac{1}{2}\right]+3\times\frac{5}{3}+\left(\frac{4}{5}+4\right)= \] \[ \frac{4}{3}+\frac{2}{9}-\left[3\times\frac{1}{9}+\frac{7}{3}\times\frac{1}{2}\right]+3\times\frac{5}{3}+\frac{24}{5}= \] \[ \frac{4}{3}+\frac{2}{9}-\frac{2+7}{6}+3\times\frac{5}{3}+\frac{24}{5}= \] \[ \frac{4}{3}+\frac{2}{9}-\frac{3}{2}+5+\frac{24}{5}=\frac{120+20-135+450+432}{90}=\frac{887}{90}=9.8\overline{5} \]

Esercizio 3 \[ \frac{2}{6}-\left[\frac{6}{4}\times\frac{1}{9}+\left(1+\frac{4}{3}\right)\div\frac{3}{2}\right]-\frac{6}{54}\times\frac{1}{3}+\left(4\times2\right)= \] \[ \frac{2}{6}-\left[\frac{6}{4}\times\frac{1}{9}+\frac{7}{3}\div\frac{3}{2}\right]-\frac{6}{54}\times\frac{1}{3}+8= \] \[ \frac{2}{6}-\left[\frac{6}{4}\times\frac{1}{9}+\frac{7}{3}\times\frac{2}{3}\right]-\frac{6}{54}\times\frac{1}{3}+8= \] \[ \frac{2}{6}-\left[\frac{2}{12}+\frac{14}{9}\right]-\frac{6}{54}\times\frac{1}{3}+8= \] \[ \frac{2}{6}-\left[\frac{1}{6}+\frac{14}{9}\right]-\frac{6}{54}\times\frac{1}{3}+8= \] \[ \frac{2}{6}-\frac{3+28}{18}-\frac{2}{54}+8= \] \[ \frac{2}{6}-\frac{3+28}{18}-\frac{1}{27}+8=\frac{18-93-2+432}{54}=\frac{355}{54} \]

Esercizio 4 \[ 3\times\left(\frac{4}{5}+3\times\frac{1}{6}+4\div\frac{2}{3}\right)-1= \] \[ 3\times\left(\frac{4}{5}+\frac{1}{2}+4\times\frac{3}{2}\right)-1= \] \[ 3\times\left(\frac{4}{5}+\frac{1}{2}+6\right)-1= \] \[ 3\times\frac{8+5+60}{10}-1=\frac{219-10}{10}=\frac{209}{10} \]